What is (x^2)/(5^2)-(y^2)/(2^2)=1 ?

The solution to (x^2)/(5^2)-(y^2)/(2^2)=1 is Hyperbola with (h,k)=(0,0),a=5,b=2

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(x^2)/(5^2)-(y^2)/(2^2)=1

\frac{x ^{2}}{5 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

(h, k) = (0, 0), a = 5, b = 2

Solution steps

\frac{x ^{2}}{5 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

Rewrite

\frac{x ^{2}}{5 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 2

y^{2} - x^{2} - 4 y + 4 x - 1 = 0

\frac{( x - 2 ) ^{2}}{4 ^{2}} - \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

16 y^{2} - 9 x^{2} = 144

4 y^{2} - 4 x^{2} - 24 x + 32 y = - 24

9 x^{2} - 16 y^{2} + 576 = 0

What is (x^2)/(5^2)-(y^2)/(2^2)=1 ?
The solution to (x^2)/(5^2)-(y^2)/(2^2)=1 is Hyperbola with (h,k)=(0,0),a=5,b=2