What is ((x-2)^2)/(4^2)-((y-3)^2)/(3^2)=1 ?

The solution to ((x-2)^2)/(4^2)-((y-3)^2)/(3^2)=1 is Hyperbola with (h,k)=(2,3),a=4,b=3

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((x-2)^2)/(4^2)-((y-3)^2)/(3^2)=1

\frac{( x - 2 ) ^{2}}{4 ^{2}} - \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

(h, k) = (2, 3), a = 4, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{4 ^{2}} - \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 3), a = 4, b = 3

16 y^{2} - 9 x^{2} = 144

4 y^{2} - 4 x^{2} - 24 x + 32 y = - 24

9 x^{2} - 16 y^{2} + 576 = 0

5 x^{2} - 5 y^{2} - 9 x - 14 y + 26 = 0

5 x^{2} - 2 y^{2} = - 3

What is ((x-2)^2)/(4^2)-((y-3)^2)/(3^2)=1 ?
The solution to ((x-2)^2)/(4^2)-((y-3)^2)/(3^2)=1 is Hyperbola with (h,k)=(2,3),a=4,b=3