What is ((x^{(2)}))/((16)+(y-4)^{(2))}=1 ?

The solution to ((x^{(2)}))/((16)+(y-4)^{(2))}=1 is Hyperbola with (h,k)=(0,4),a=4,b=4

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((x^{(2)}))/((16)+(y-4)^{(2))}=1

\frac{( x ^{(2)} )}{( 16 ) + ( y - 4 ) ^{(2)}} = 1

(h, k) = (0, 4), a = 4, b = 4

Solution steps

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

Rewrite

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 4 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 4), a = 4, b = 4

- 9 x^{2} + 25 y^{2} - 100 y - 125 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{11} = 1

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

4 y^{2} - x^{2} - 12 y - 16 x + 16 = 0

- 4 x^{2} + y^{2} = 16

What is ((x^{(2)}))/((16)+(y-4)^{(2))}=1 ?
The solution to ((x^{(2)}))/((16)+(y-4)^{(2))}=1 is Hyperbola with (h,k)=(0,4),a=4,b=4