What is -4x^2+y^2=16 ?

The solution to -4x^2+y^2=16 is Hyperbola with (h,k)=(0,0),a=4,b=2

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-4x^2+y^2=16

- 4 x^{2} + y^{2} = 16

(h, k) = (0, 0), a = 4, b = 2

Solution steps

- 4 x^{2} + y^{2} = 16

Rewrite

- 4 x^{2} + y^{2} = 16

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

y^{2} - x^{2} = 9

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

3 x^{2} - y^{2} - 18 x + 4 y + 11 = 0

4 x^{2} - y^{2} = - 16

25 y^{2} - 16 x^{2} = 400

What is -4x^2+y^2=16 ?
The solution to -4x^2+y^2=16 is Hyperbola with (h,k)=(0,0),a=4,b=2