What is the axis ((y+4)^2)/9+((x-9)^2)/(25)=1 ?

The axis ((y+4)^2)/9+((x-9)^2)/(25)=1 is semi-major axis a=5, semi-minor axis b=3

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axis ((y+4)^2)/9+((x-9)^2)/(25)=1

axis

\frac{( y + 4 ) ^{2}}{9} + \frac{( x - 9 ) ^{2}}{25} = 1

semi - major axis a = 5, semi - minor axis b = 3

Solution steps

\frac{( y + 4 ) ^{2}}{9} + \frac{( x - 9 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 4 ) ^{2}}{9} + \frac{( x - 9 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 9 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (9, - 4), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (9, - 4), a = 5, b = 3

25 x^{2} + 16 y^{2} = 400

x^{2} + 2 y^{2} = 2

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

What is the axis ((y+4)^2)/9+((x-9)^2)/(25)=1 ?
The axis ((y+4)^2)/9+((x-9)^2)/(25)=1 is semi-major axis a=5, semi-minor axis b=3