What is the axis 25x^2+16y^2=400 ?

The axis 25x^2+16y^2=400 is semi-major axis b=5, semi-minor axis a=4

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axis 25x^2+16y^2=400

axis

25 x^{2} + 16 y^{2} = 400

semi - major axis b = 5, semi - minor axis a = 4

Solution steps

25 x^{2} + 16 y^{2} = 400

Rewrite

25 x^{2} + 16 y^{2} = 400

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 4

x^{2} + 2 y^{2} = 2

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

What is the axis 25x^2+16y^2=400 ?
The axis 25x^2+16y^2=400 is semi-major axis b=5, semi-minor axis a=4