What is the eccentricity (x^2)/5+(y^2)/(20.98)=1 ?

The eccentricity (x^2)/5+(y^2)/(20.98)=1 is 0.87274…

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eccentricity (x^2)/5+(y^2)/(20.98)=1

eccentricity

\frac{x ^{2}}{5} + \frac{y ^{2}}{20.98} = 1

0.87274 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{5} + \frac{y ^{2}}{20.98} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 20.98, a = 5

= \frac{( 20.98 ) ^{2} - ( 5 ) ^{2}}{20.98}

\frac{( 20.98 ) ^{2} - ( 5 ) ^{2}}{20.98} = 0.87274 \dots

= 0.87274 \dots

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

x^{2} + y^{2} = 1

x^{2} + 2 y^{2} = 3

4 x^{2} + 9 y^{2} = 144

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

What is the eccentricity (x^2)/5+(y^2)/(20.98)=1 ?
The eccentricity (x^2)/5+(y^2)/(20.98)=1 is 0.87274…