exzentrizität 16x^2+192x+576+25y^2=1600

Lösung

exzentrizität

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

\frac{3}{5}

Dezimale

0.6

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600 :

Ellipse with center

(h, k) = (- 6, 0), a = 10, b = 8

= \frac{1 0 ^{2} - 8 ^{2}}{10}

\frac{1 0 ^{2} - 8 ^{2}}{10} = \frac{3}{5}

= \frac{3}{5}

ecce n t r i c i t y x^{2} + 2 y^{2} = 3

ecce n t r i c i t y 4 x^{2} + 9 y^{2} = 144

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

ecce n t r i c i t y \frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

ecce n t r i c i t y 18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0