What is the eccentricity (x^2)/8+(y^2)/4 =1 ?

The eccentricity (x^2)/8+(y^2)/4 =1 is 1/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/8+(y^2)/4 =1

eccentricity

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

\frac{1}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 22, b = 2

= \frac{( 2 2 ) ^{2} - 2 ^{2}}{2 2}

\frac{( 2 2 ) ^{2} - 2 ^{2}}{2 2} = \frac{1}{2}

= \frac{1}{2}

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

\frac{( x ) ^{2}}{12} + \frac{( y ) ^{2}}{16} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

9 x^{2} + 49 y^{2} = 441

What is the eccentricity (x^2)/8+(y^2)/4 =1 ?
The eccentricity (x^2)/8+(y^2)/4 =1 is 1/(sqrt(2))