What is the eccentricity 9x^2+49y^2=441 ?

The eccentricity 9x^2+49y^2=441 is (2sqrt(10))/7

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eccentricity 9x^2+49y^2=441

eccentricity

9 x^{2} + 49 y^{2} = 441

\frac{2 10}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

9 x^{2} + 49 y^{2} = 441 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 3

= \frac{7 ^{2} - 3 ^{2}}{7}

\frac{7 ^{2} - 3 ^{2}}{7} = \frac{2 10}{7}

= \frac{2 10}{7}

\frac{x ^{2}}{324} + \frac{y ^{2}}{400} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

4 x^{2} + 3 y^{2} + 24 x + 36 y + 72 = 0

\frac{5}{81} x^{2} + \frac{y ^{2}}{9} = 1

3 x^{2} + y^{2} - 24 x = - 39

What is the eccentricity 9x^2+49y^2=441 ?
The eccentricity 9x^2+49y^2=441 is (2sqrt(10))/7