What is the eccentricity 3x^2+2y^2=6 ?

The eccentricity 3x^2+2y^2=6 is 1/(sqrt(3))

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eccentricity 3x^2+2y^2=6

eccentricity

3 x^{2} + 2 y^{2} = 6

\frac{1}{3}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

3 x^{2} + 2 y^{2} = 6 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 2

= \frac{( 3 ) ^{2} - ( 2 ) ^{2}}{3}

\frac{( 3 ) ^{2} - ( 2 ) ^{2}}{3} = \frac{1}{3}

= \frac{1}{3}

3 x^{2} + 7 y^{2} = 63

\frac{x ^{2}}{160} + \frac{y ^{2}}{16} = 1

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

What is the eccentricity 3x^2+2y^2=6 ?
The eccentricity 3x^2+2y^2=6 is 1/(sqrt(3))