What is the eccentricity (y^2}{16}+\frac{x^2)/9 =1 ?

The eccentricity (y^2}{16}+\frac{x^2)/9 =1 is (sqrt(7))/4

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eccentricity (y^2}{16}+\frac{x^2)/9 =1

eccentricity

\frac{y ^{2}}{16} + \frac{x ^{2}}{9} = 1

\frac{7}{4}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{y ^{2}}{16} + \frac{x ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 3

= \frac{4 ^{2} - 3 ^{2}}{4}

\frac{4 ^{2} - 3 ^{2}}{4} = \frac{7}{4}

= \frac{7}{4}

2 x^{2} + 8 y^{2} = 16

\frac{x ^{2}}{4} + \frac{y ^{2}}{3.2} = 1

9 x^{2} + 7 y^{2} = 63

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

x^{2} + 16 y^{2} - 64 = 0

What is the eccentricity (y^2}{16}+\frac{x^2)/9 =1 ?
The eccentricity (y^2}{16}+\frac{x^2)/9 =1 is (sqrt(7))/4