exzentrizität 2x^2+7y^2=14

Lösung

exzentrizität

2 x^{2} + 7 y^{2} = 14

\frac{5}{7}

Dezimale

0.84515 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

2 x^{2} + 7 y^{2} = 14 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 2

= \frac{( 7 ) ^{2} - ( 2 ) ^{2}}{7}

\frac{( 7 ) ^{2} - ( 2 ) ^{2}}{7} = \frac{5}{7}

= \frac{5}{7}

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