What is the eccentricity (x/8)^2+(y/6)^2=1 ?

The eccentricity (x/8)^2+(y/6)^2=1 is (sqrt(7))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x/8)^2+(y/6)^2=1

eccentricity

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

\frac{7}{4}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 6

= \frac{8 ^{2} - 6 ^{2}}{8}

\frac{8 ^{2} - 6 ^{2}}{8} = \frac{7}{4}

= \frac{7}{4}

4 x^{2} + 9 y^{2} - 8 x - 32 = 0

9 x^{2} + 6 y^{2} = 54

3 x^{2} + 10 y^{2} = 30

x^{2} + 4 y^{2} = 10

\frac{y ^{2}}{16} + \frac{x ^{2}}{9} = 1

What is the eccentricity (x/8)^2+(y/6)^2=1 ?
The eccentricity (x/8)^2+(y/6)^2=1 is (sqrt(7))/4