What is the center 49x^2+625y^2=30625 ?

The center 49x^2+625y^2=30625 is (0,0)

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center 49x^2+625y^2=30625

center

49 x^{2} + 625 y^{2} = 30625

(0, 0)

Solution steps

49 x^{2} + 625 y^{2} = 30625

Rewrite

49 x^{2} + 625 y^{2} = 30625

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 5 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 25, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 25, b = 7

And the center is:

(0, 0)

4 x^{2} + 9 y^{2} - 24 x + 36 y + 36 = 0

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

\frac{x ^{2}}{16} + \frac{( y + 1 ) ^{2}}{4} - 1 = 0

3 x^{2} + 3 y^{2} - 12 y = 0

\frac{( x - 4 ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1