center ((x-10)^2)/4+(y^2)/(16)=1

Lösung

center

\frac{( x - 10 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

(10, 0)

Schritte zur Lösung

\frac{( x - 10 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{( x - 10 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 10 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (10, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (10, 0), b = 4, a = 2

And the center is:

(10, 0)

ce n t er 25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

ce n t er 25 (x + 1)^{2} + 9 (y - 2)^{2} = 225

ce n t er (\frac{( x - 2 ) ^{2}}{16}) + (\frac{y ^{2}}{9}) = 1

ce n t er \frac{( x - 6 ) ^{2}}{5} + \frac{( y + 1 ) ^{2}}{6} = 1

ce n t er 36 x^{2} + 5 y^{2} - 90 y - 495 = 0