foki 4x^2+y^2+40x+6y+95=0

Lösung

foki

4 x^{2} + y^{2} + 40 x + 6 y + 95 = 0

(- 5, - 3 + \frac{21}{2}), (- 5, - 3 - \frac{21}{2})

Schritte zur Lösung

(h, k + c), (h, k - c)

Calculate ellipse properties

4 x^{2} + y^{2} + 40 x + 6 y + 95 = 0 :

Ellipse with center

(h, k) = (- 5, - 3), b = 14, a = \frac{7}{2}

(- 5, - 3 + c), (- 5, - 3 - c)

Compute

c :

c = 14^{2} - \frac{7}{2}^{2} : \frac{21}{2}

(- 5, - 3 + \frac{21}{2}), (- 5, - 3 - \frac{21}{2})

f oc i 49 x^{2} + 25 y^{2} = 1225

f oc i \frac{( x - 4 ) ^{2}}{32} + \frac{( y - 3 ) ^{2}}{36} = 1

f oc i \frac{x ^{2}}{289} + \frac{y ^{2}}{225} = 1

f oc i \frac{( x + 3 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{9} = 1

f oc i 9 x^{2} + 25 y^{2} + 54 x + 100 y - 44 = 0