What is the vertices 4x^2+9y^2-48x+72y=-144 ?

The vertices 4x^2+9y^2-48x+72y=-144 is (12,-4),(0,-4)

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vertices 4x^2+9y^2-48x+72y=-144

vertices

4 x^{2} + 9 y^{2} - 48 x + 72 y = - 144

(12, - 4), (0, - 4)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 48 x + 72 y = - 144 :

Ellipse with center

(h, k) = (6, - 4), a = 6, b = 4

(6 + 6, - 4), (6 - 6, - 4)

Refine

(12, - 4), (0, - 4)

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

4 x^{2} + 9 y^{2} - 16 x - 18 y - 11 = 0

x^{2} + 3 y^{2} = 6

x^{2} + 3 y^{2} - 6 x + 6 y = 0

7 x^{2} + 9 y^{2} = 63

What is the vertices 4x^2+9y^2-48x+72y=-144 ?
The vertices 4x^2+9y^2-48x+72y=-144 is (12,-4),(0,-4)