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Popular >

vertices x^2+3y^2=6

Solution

vertices

x^{2} + 3 y^{2} = 6

Solution

(6, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 3 y^{2} = 6 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 2

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

Popular Examples

vertices x^2+3y^2-6x+6y=0 vertices

x^{2} + 3 y^{2} - 6 x + 6 y = 0

vertices 7x^2+9y^2=63 vertices

7 x^{2} + 9 y^{2} = 63

vertices (x^2)/(81)+(y^2)/(225)=1 vertices

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1

vertices 25x^2+16y^2+100x-96y=156 vertices

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

vertices 300x^2+150y^2=50 vertices

300 x^{2} + 150 y^{2} = 50

Frequently Asked Questions (FAQ)

What is the vertices x^2+3y^2=6 ?
The vertices x^2+3y^2=6 is (sqrt(6),0),(-sqrt(6),0)