What is the vertices 25x^2+9y^2-225=0 ?

The vertices 25x^2+9y^2-225=0 is (0,5),(0,-5)

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vertices 25x^2+9y^2-225=0

vertices

25 x^{2} + 9 y^{2} - 225 = 0

(0, 5), (0, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 9 y^{2} - 225 = 0 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

64 x^{2} + y^{2} = 64

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

6 x^{2} + 6 y^{2} + 24 x + 36 y = 0

64 x^{2} + 9 y^{2} = 576

x^{2} + \frac{y ^{2}}{4} = 1

What is the vertices 25x^2+9y^2-225=0 ?
The vertices 25x^2+9y^2-225=0 is (0,5),(0,-5)