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Popular >

vertices 64x^2+y^2=64

Solution

vertices

64 x^{2} + y^{2} = 64

Solution

(0, 8), (0, - 8)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

64 x^{2} + y^{2} = 64 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 1

(0, 0 + 8), (0, 0 - 8)

Refine

(0, 8), (0, - 8)

Popular Examples

vertices (x^2)/(36)+(y^2)/(100)=1 vertices

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

vertices 6x^2+6y^2+24x+36y=0 vertices

6 x^{2} + 6 y^{2} + 24 x + 36 y = 0

vertices 64x^2+9y^2=576 vertices

64 x^{2} + 9 y^{2} = 576

vertices x^2+(y^2)/4 =1 vertices

x^{2} + \frac{y ^{2}}{4} = 1

vertices (x^2)/(100)+(y^2)/(44)=1 vertices

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

Frequently Asked Questions (FAQ)

What is the vertices 64x^2+y^2=64 ?
The vertices 64x^2+y^2=64 is (0,8),(0,-8)