What is the vertices 6x^2+6y^2+24x+36y=0 ?

The vertices 6x^2+6y^2+24x+36y=0 is (-2,-3+sqrt(13)),(-2,-3-sqrt(13))

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vertices 6x^2+6y^2+24x+36y=0

vertices

6 x^{2} + 6 y^{2} + 24 x + 36 y = 0

(- 2, - 3 + 13), (- 2, - 3 - 13)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

6 x^{2} + 6 y^{2} + 24 x + 36 y = 0 :

Ellipse with center

(h, k) = (- 2, - 3), b = 13, a = 13

(- 2, - 3 + 13), (- 2, - 3 - 13)

64 x^{2} + 9 y^{2} = 576

x^{2} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

25 x^{2} + 144 y^{2} = 900

What is the vertices 6x^2+6y^2+24x+36y=0 ?
The vertices 6x^2+6y^2+24x+36y=0 is (-2,-3+sqrt(13)),(-2,-3-sqrt(13))