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Popular >

vertices x^2+2y^2-1=0

Solution

vertices

x^{2} + 2 y^{2} - 1 = 0

Solution

(1, 0), (- 1, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 2 y^{2} - 1 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

Popular Examples

vertices 9x^2+25y^2=9 vertices

9 x^{2} + 25 y^{2} = 9

vertices (x^2}{36}+\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{36} + \frac{y ^{2}}{9} = 1

vertices 81x^2+4y^2=324 vertices

81 x^{2} + 4 y^{2} = 324

vertices x^2-4x+100y^2+200y+4=0 vertices

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

vertices 9x^2-54x+y^2+2y+46=0 vertices

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

Frequently Asked Questions (FAQ)

What is the vertices x^2+2y^2-1=0 ?
The vertices x^2+2y^2-1=0 is (1,0),(-1,0)