What is (p(x)}{2/5 (x-1)+2}=\frac{x+2)/3-6 ?

The solution to (p(x)}{2/5 (x-1)+2}=\frac{x+2)/3-6 is Parabola with (h,k)=(6,-40/3),p= 15/8

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(p(x)}{2/5 (x-1)+2}=\frac{x+2)/3-6

\frac{p ( x )}{\frac{2}{5} ( x - 1 ) + 2} = \frac{x + 2}{3} - 6

(h, k) = (6, - \frac{40}{3}), p = \frac{15}{8}

Solution steps

\frac{y}{\frac{2}{5} ( x - 1 ) + 2} = \frac{x + 2}{3} - 6

Rewrite

\frac{y}{\frac{2}{5} ( x - 1 ) + 2} - \frac{x + 2}{3} + 6 = 0

in the standard form

4 \cdot \frac{15}{8} (y - (- \frac{40}{3})) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - \frac{40}{3}), p = \frac{15}{8}

x = 8 y^{2} - 16 y + 1

1 - f (x) = x^{2} - 6 x + 10

3 x^{2} - 9 y = 0

2 f (x) = 3 x^{2} - x + 2

x^{2} - 6 x + y = 0

What is (p(x)}{2/5 (x-1)+2}=\frac{x+2)/3-6 ?
The solution to (p(x)}{2/5 (x-1)+2}=\frac{x+2)/3-6 is Parabola with (h,k)=(6,-40/3),p= 15/8