1-f(x)=x^2-6x+10

Lösung

1 - f (x) = x^{2} - 6 x + 10

(h, k) = (3, 0), p = - \frac{1}{4}

Schritte zur Lösung

1 - y = x^{2} - 6 x + 10

Rewrite

1 - y = x^{2} - 6 x + 10

in the standard form

4 (- \frac{1}{4}) (y - 0) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = - \frac{1}{4}

3 x^{2} - 9 y = 0

2 f (x) = 3 x^{2} - x + 2

x^{2} - 6 x + y = 0

x^{2} + (y - 5) 2 = 16

x^{2} + 3 x + 2 m (x) - 1 = 0