What is ((x+4)^2)/(16)+((y-1)^2)/(36)=1 ?

The solution to ((x+4)^2)/(16)+((y-1)^2)/(36)=1 is Ellipse with (h,k)=(-4,1),a=4,b=6

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((x+4)^2)/(16)+((y-1)^2)/(36)=1

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

(h, k) = (- 4, 1), a = 4, b = 6

Solution steps

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{4 ^{2}} + \frac{( y - 1 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 1), a = 4, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 4, 1), b = 6, a = 4

x^{2} + \frac{y ^{2}}{12} = 1

25 X^{2} + 4 Y^{2} - 250 X - 16 Y + 541 = 0

(\frac{x ^{2}}{169}) + (\frac{y ^{2}}{144}) = 1

- 8 y^{2} - 10 y + 72 = 9 x^{2}

Y^{2} + 2 X^{2} - 2 Y + 4 X - 6 = 0

What is ((x+4)^2)/(16)+((y-1)^2)/(36)=1 ?
The solution to ((x+4)^2)/(16)+((y-1)^2)/(36)=1 is Ellipse with (h,k)=(-4,1),a=4,b=6