What is 25X^2+4Y^2-250X-16Y+541=0 ?

The solution to 25X^2+4Y^2-250X-16Y+541=0 is Ellipse with (h,k)=(5,2),a=2,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25X^2+4Y^2-250X-16Y+541=0

25 X^{2} + 4 Y^{2} - 250 X - 16 Y + 541 = 0

(h, k) = (5, 2), a = 2, b = 5

Solution steps

25 X^{2} + 4 Y^{2} - 250 X - 16 Y + 541 = 0

Rewrite

25 X^{2} + 4 Y^{2} - 250 X - 16 Y + 541 = 0

in the form of the standard ellipse equation

\frac{( X - 5 ) ^{2}}{2 ^{2}} + \frac{( Y - 2 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, 2), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (5, 2), b = 5, a = 2

(\frac{x ^{2}}{169}) + (\frac{y ^{2}}{144}) = 1

- 8 y^{2} - 10 y + 72 = 9 x^{2}

Y^{2} + 2 X^{2} - 2 Y + 4 X - 6 = 0

8 x^{2} + 8 y^{2} + 16 y = 0

\frac{x ^{2} + 12 x + 36}{100} + \frac{y ^{2}}{64} = 1

What is 25X^2+4Y^2-250X-16Y+541=0 ?
The solution to 25X^2+4Y^2-250X-16Y+541=0 is Ellipse with (h,k)=(5,2),a=2,b=5