What is 55x^2+5y^2=4 ?

The solution to 55x^2+5y^2=4 is Ellipse with (h,k)=(0,0),a= 2/(sqrt(55)),b= 2/(sqrt(5))

Popular >

55x^2+5y^2=4

55 x^{2} + 5 y^{2} = 4

(h, k) = (0, 0), a = \frac{2}{55}, b = \frac{2}{5}

Solution steps

55 x^{2} + 5 y^{2} = 4

Rewrite

55 x^{2} + 5 y^{2} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{2}{55} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{2}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{2}{55}, b = \frac{2}{5}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{2}{5}, a = \frac{2}{55}

81 (x - 2)^{2} + 36 (y - 3)^{2} = 2916

3 x^{2} + 5 y^{2} - 6 x - 20 y + 8 = 0

\frac{( x + \frac{17}{2} ) ^{2}}{144} + \frac{( y + \frac{13}{2} ) ^{2}}{121} = 1

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

0^{2} = (- 16 - x^{2} - y^{2})^{2}

What is 55x^2+5y^2=4 ?
The solution to 55x^2+5y^2=4 is Ellipse with (h,k)=(0,0),a= 2/(sqrt(55)),b= 2/(sqrt(5))