What is 0^2=(-sqrt(16-x^2-y^2))^2 ?

The solution to 0^2=(-sqrt(16-x^2-y^2))^2 is Ellipse with (h,k)=(0,0),a=4,b=4

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0^2=(-sqrt(16-x^2-y^2))^2

0^{2} = (- 16 - x^{2} - y^{2})^{2}

(h, k) = (0, 0), a = 4, b = 4

Solution steps

0^{2} = (- 16 - x^{2} - y^{2})^{2}

Rewrite

0^{2} - (- 16 - x^{2} - y^{2})^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 4

150 = 60 x - 2 x^{2} + 80 y - 4 y^{2}

16 x^{2} + 25 y^{2} + 100 y = 300

25 x^{2} + 4 y^{2} - 50 x + 8 y - 71 = 0

16 x^{2} - 64 x + 25 y^{2} + 100 y = 236

9 x^{2} + 11 y^{2} = 10

What is 0^2=(-sqrt(16-x^2-y^2))^2 ?
The solution to 0^2=(-sqrt(16-x^2-y^2))^2 is Ellipse with (h,k)=(0,0),a=4,b=4