What is (x^2)/(16)+(y^2)/(48)=1 ?

The solution to (x^2)/(16)+(y^2)/(48)=1 is Ellipse with (h,k)=(0,0),a=4,b=4sqrt(3)

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(x^2)/(16)+(y^2)/(48)=1

\frac{x ^{2}}{16} + \frac{y ^{2}}{48} = 1

(h, k) = (0, 0), a = 4, b = 43

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{48} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{48} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{( 4 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 43

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 43, a = 4

9^{2} x^{2} + 7^{2} y^{2} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{5} = 1

16 (x + 1)^{2} + y^{2} = 16

16 x^{2} + 9 y^{2} - 128 x - 90 y + 337 = 0

(x + 6)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{16}} = 1

What is (x^2)/(16)+(y^2)/(48)=1 ?
The solution to (x^2)/(16)+(y^2)/(48)=1 is Ellipse with (h,k)=(0,0),a=4,b=4sqrt(3)