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Popular >

16(x+1)^2+y^2=16

Solution

16 (x + 1)^{2} + y^{2} = 16

Solution

(h, k) = (- 1, 0), a = 1, b = 4

Solution steps

16 (x + 1)^{2} + y^{2} = 16

Rewrite

16 (x + 1)^{2} + y^{2} = 16

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 1, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), b = 4, a = 1

Popular Examples

16x^2+9y^2-128x-90y+337=0

16 x^{2} + 9 y^{2} - 128 x - 90 y + 337 = 0

(x+6)^2+((y+4)^2)/(1/16)=1

(x + 6)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{16}} = 1

4(x-1)^2+9y^2=36

4 (x - 1)^{2} + 9 y^{2} = 36

((x^2+6x+9))/(49)+((y^2-2y+1))/(45)=1

\frac{( x ^{2} + 6 x + 9 )}{49} + \frac{( y ^{2} - 2 y + 1 )}{45} = 1

((y-5)^2}{16}+\frac{(x-3)^2)/4 =1

\frac{( y - 5 ) ^{2}}{16} + \frac{( x - 3 ) ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is 16(x+1)^2+y^2=16 ?
The solution to 16(x+1)^2+y^2=16 is Ellipse with (h,k)=(-1,0),a=1,b=4