What is ((X+2)^2)/4+((y-3)^2)/9 =1 ?

The solution to ((X+2)^2)/4+((y-3)^2)/9 =1 is Ellipse with (h,k)=(-2,3),a=2,b=3

Popular >

((X+2)^2)/4+((y-3)^2)/9 =1

\frac{( X + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

(h, k) = (- 2, 3), a = 2, b = 3

Solution steps

\frac{( X + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

Rewrite

\frac{( X + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( X - ( - 2 ) ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 3), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 3), b = 3, a = 2

7 x^{2} + 16 y^{2} - 112 = 0

(x - h)^{2} + (y - k)^{2} = 1

9 x^{2} + 64 y^{2} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{25} = 1

y + 2 = \frac{6 - ( \frac{6 y + 2 x}{2 + y} )}{2} x

What is ((X+2)^2)/4+((y-3)^2)/9 =1 ?
The solution to ((X+2)^2)/4+((y-3)^2)/9 =1 is Ellipse with (h,k)=(-2,3),a=2,b=3