What is ((x-1)^2)/(36)+((y+1)^2)/(25)=1 ?

The solution to ((x-1)^2)/(36)+((y+1)^2)/(25)=1 is Ellipse with (h,k)=(1,-1),a=6,b=5

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((x-1)^2)/(36)+((y+1)^2)/(25)=1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

(h, k) = (1, - 1), a = 6, b = 5

Solution steps

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{6 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 1), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, - 1), a = 6, b = 5

8 x^{2} + 9 y^{2} - 16 x - 18 y - 55 = 0

\frac{x ^{2}}{576} + \frac{y ^{2}}{676} = 1

9 x^{2} + y^{2} - 18 x - 6 y + 9 = 0

25 x^{2} + 10 y^{2} = 50

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{64} = 1

What is ((x-1)^2)/(36)+((y+1)^2)/(25)=1 ?
The solution to ((x-1)^2)/(36)+((y+1)^2)/(25)=1 is Ellipse with (h,k)=(1,-1),a=6,b=5