What is 25x^2+10y^2=50 ?

The solution to 25x^2+10y^2=50 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25x^2+10y^2=50

25 x^{2} + 10 y^{2} = 50

(h, k) = (0, 0), a = 2, b = 5

Solution steps

25 x^{2} + 10 y^{2} = 50

Rewrite

25 x^{2} + 10 y^{2} = 50

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 2

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{64} = 1

2 x^{2} + 7 y^{2} = 14

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

x^{2} + (\frac{y ^{2}}{4}) = 1

4 = 4 x^{2} + y^{2} + 1

What is 25x^2+10y^2=50 ?
The solution to 25x^2+10y^2=50 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(5)