What is ((2x^2)/(25))+(((y-3)^2)/(49))=1 ?

The solution to ((2x^2)/(25))+(((y-3)^2)/(49))=1 is Ellipse with (h,k)=(0,3),a= 5/(sqrt(2)),b=7

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((2x^2)/(25))+(((y-3)^2)/(49))=1

(\frac{2 x ^{2}}{25}) + (\frac{( y - 3 ) ^{2}}{49}) = 1

(h, k) = (0, 3), a = \frac{5}{2}, b = 7

Solution steps

\frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

Rewrite

\frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} + \frac{( y - 3 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 3), a = \frac{5}{2}, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 3), b = 7, a = \frac{5}{2}

(x + 2)^{2} - 1 = - 4 (y + 1)^{2}

9 x^{2} + 4 y^{2} - 18 x + 24 y = 0

27 x^{2} + 48 y^{2} = 192 y + 54 x + 213

x, x^{2} + \frac{π R ( x ) ^{2}}{2} = 200

\frac{( x ^{2} )}{( 29 )} + \frac{( y ^{2} )}{( 24 )} = 1

What is ((2x^2)/(25))+(((y-3)^2)/(49))=1 ?
The solution to ((2x^2)/(25))+(((y-3)^2)/(49))=1 is Ellipse with (h,k)=(0,3),a= 5/(sqrt(2)),b=7