What is ((x^2))/((29))+((y^2))/((24))=1 ?

The solution to ((x^2))/((29))+((y^2))/((24))=1 is Ellipse with (h,k)=(0,0),a=sqrt(29),b=2sqrt(6)

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((x^2))/((29))+((y^2))/((24))=1

\frac{( x ^{2} )}{( 29 )} + \frac{( y ^{2} )}{( 24 )} = 1

(h, k) = (0, 0), a = 29, b = 26

Solution steps

\frac{x ^{2}}{29} + \frac{y ^{2}}{24} = 1

Rewrite

\frac{x ^{2}}{29} + \frac{y ^{2}}{24} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 29 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 29, b = 26

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 29, b = 26

36 x^{2} + 16 y^{2} + 96 y - 180 x - 207 = 0

x^{2} + y^{2} - 4 y + 2^{2} = 2^{2}

7 x^{2} - 28 x + 4 y^{2} + 8 y = - 4

2 x^{2} + 3 y^{2} - 4 x + 12 y - 20 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

What is ((x^2))/((29))+((y^2))/((24))=1 ?
The solution to ((x^2))/((29))+((y^2))/((24))=1 is Ellipse with (h,k)=(0,0),a=sqrt(29),b=2sqrt(6)