What is 4x^2+8y^2-16=0 ?

The solution to 4x^2+8y^2-16=0 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)

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4x^2+8y^2-16=0

4 x^{2} + 8 y^{2} - 16 = 0

(h, k) = (0, 0), a = 2, b = 2

Solution steps

4 x^{2} + 8 y^{2} - 16 = 0

Rewrite

4 x^{2} + 8 y^{2} - 16 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 2

17 x^{2} + 10 y^{2} + 102 x + 80 y + 143 = 0

(6 p + 5 q) 2 = 36 p^{2} + 25 q^{2}

3 x^{2} + 54 x + 243 + 2 y^{2} - 6 = 0

4 x^{2} + 9 y^{2} - 24 x + 36 y - 72 = 0

0.04 = 0.01 x^{2} + 0.04 y^{2}

What is 4x^2+8y^2-16=0 ?
The solution to 4x^2+8y^2-16=0 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)