What is 0.04=0.01x^2+0.04y^2 ?

The solution to 0.04=0.01x^2+0.04y^2 is Ellipse with (h,k)=(0,0),a=2,b=1

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0.04=0.01x^2+0.04y^2

0.04 = 0.01 x^{2} + 0.04 y^{2}

(h, k) = (0, 0), a = 2, b = 1

Solution steps

0.04 = 0.01 x^{2} + 0.04 y^{2}

Rewrite

0.04 = 0.01 x^{2} + 0.04 y^{2}

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

3 x^{2} + 2 y^{2} \geq 18

144 y^{2} + 169 x^{2} = 169 \cdot 144

4 x^{2} + 9 y^{2} = 16

8 x^{2} + 9 y^{2} + 24 x + 12 y + 10 = 0

4 x^{2} + y^{2} - 8 x - 6 y - 3 = 0

What is 0.04=0.01x^2+0.04y^2 ?
The solution to 0.04=0.01x^2+0.04y^2 is Ellipse with (h,k)=(0,0),a=2,b=1