What is (x^2)/(144)+(y^2)/(16)=1 ?

The solution to (x^2)/(144)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=12,b=4

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(x^2)/(144)+(y^2)/(16)=1

\frac{x ^{2}}{144} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 12, b = 4

Solution steps

\frac{x ^{2}}{144} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{144} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 12, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 12, b = 4

(2 x - 2)^{2} + (3 y - 6)^{2} = 36

\frac{x ^{2}}{12} + \frac{y ^{2}}{16} = 1

\frac{3}{2} u^{2} + \frac{1}{2} v^{2} = 4

4 x^{2} + 16 x + 5 y^{2} - 10 y + 1 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} + \frac{x ^{2}}{9} = 1

What is (x^2)/(144)+(y^2)/(16)=1 ?
The solution to (x^2)/(144)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=12,b=4