What is x^2+4y^2=20 ?

The solution to x^2+4y^2=20 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=sqrt(5)

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x^2+4y^2=20

x^{2} + 4 y^{2} = 20

(h, k) = (0, 0), a = 25, b = 5

Solution steps

x^{2} + 4 y^{2} = 20

Rewrite

x^{2} + 4 y^{2} = 20

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 25, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 25, b = 5

8 x^{2} + z^{2} = 36

\frac{( x - 1.23 ) ^{2}}{1.4 1 ^{2}} + \frac{y ^{2}}{1.00 7 ^{2}} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{5} = 1

9 x^{(2)} - 54 x + y^{(2)} - 2 y = - 81

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y + 3 ) ^{2}}{5 ^{2}} = 1

What is x^2+4y^2=20 ?
The solution to x^2+4y^2=20 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=sqrt(5)