What is (x^2)/(400)+(y^2)/(100)=1 ?

The solution to (x^2)/(400)+(y^2)/(100)=1 is Ellipse with (h,k)=(0,0),a=20,b=10

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(x^2)/(400)+(y^2)/(100)=1

\frac{x ^{2}}{400} + \frac{y ^{2}}{100} = 1

(h, k) = (0, 0), a = 20, b = 10

Solution steps

\frac{x ^{2}}{400} + \frac{y ^{2}}{100} = 1

Rewrite

\frac{x ^{2}}{400} + \frac{y ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 0 ^{2}} + \frac{( y - 0 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 20, b = 10

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 20, b = 10

\frac{( x + 2 ) ^{2}}{25} + (\frac{( y + 2 )}{9})^{2} = 1

\frac{( x - 3 ) ^{2}}{7} + \frac{y ^{2}}{15} = 1

x^{2} - 6 x + 4 y^{2} + 16 y + 21 = 0

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{25} = 1

16 x^{2} + 36 y^{2} - 96 x + 36 y + 9 = 0

What is (x^2)/(400)+(y^2)/(100)=1 ?
The solution to (x^2)/(400)+(y^2)/(100)=1 is Ellipse with (h,k)=(0,0),a=20,b=10