What is 4x^2-16x+y^2+2y+13=0 ?

The solution to 4x^2-16x+y^2+2y+13=0 is Ellipse with (h,k)=(2,-1),a=1,b=2

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4x^2-16x+y^2+2y+13=0

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

(h, k) = (2, - 1), a = 1, b = 2

Solution steps

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

Rewrite

4 x^{2} - 16 x + y^{2} + 2 y + 13 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{1 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), b = 2, a = 1

\frac{( x + 3 ) ^{2}}{49} + \frac{( y + 2 ) ^{2}}{21} = 1

3 x^{2} + 2 y^{2} - 16 x + 15 = 0

\frac{x ^{2}}{400} + \frac{y ^{2}}{100} = 1

\frac{( x + 2 ) ^{2}}{25} + (\frac{( y + 2 )}{9})^{2} = 1

\frac{( x - 3 ) ^{2}}{7} + \frac{y ^{2}}{15} = 1

What is 4x^2-16x+y^2+2y+13=0 ?
The solution to 4x^2-16x+y^2+2y+13=0 is Ellipse with (h,k)=(2,-1),a=1,b=2