What is -(x-2)^2-y^2=4 ?

The solution to -(x-2)^2-y^2=4 is Ellipse with (h,k)=(2,0),a=2,b=2

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-(x-2)^2-y^2=4

- (x - 2)^{2} - y^{2} = 4

(h, k) = (2, 0), a = 2, b = 2

Solution steps

- (x - 2)^{2} - y^{2} = 4

Rewrite

- (x - 2)^{2} - y^{2} = 4

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 2, a = 2

\frac{x ^{2}}{5.6 6 ^{2}} + \frac{y ^{2}}{3.5 9 ^{2}} = 1

5 x^{2} + 2 y^{2} = 1

5 x^{2} + 2 y^{2} = 2

3 (x - 5)^{2} + 4 (y + 1)^{2} = 6

- 8 y^{2} + 72 < 9 x^{2}

What is -(x-2)^2-y^2=4 ?
The solution to -(x-2)^2-y^2=4 is Ellipse with (h,k)=(2,0),a=2,b=2