What is (((x+1)^2)/4)+y^2=1 ?

The solution to (((x+1)^2)/4)+y^2=1 is Ellipse with (h,k)=(-1,0),a=2,b=1

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(((x+1)^2)/4)+y^2=1

(\frac{( x + 1 ) ^{2}}{4}) + y^{2} = 1

(h, k) = (- 1, 0), a = 2, b = 1

Solution steps

\frac{( x + 1 ) ^{2}}{4} + y^{2} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{4} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), a = 2, b = 1

\frac{( x - 5 ) ^{2}}{49} + \frac{( y + 4 ) ^{2}}{81} = 1

x^{2} + 9 y^{2} \leq 16

(\frac{x - 2}{2})^{2} + (\frac{y + 3}{4})^{2} = 1

- (x - 2)^{2} - y^{2} = 4

\frac{x ^{2}}{5.6 6 ^{2}} + \frac{y ^{2}}{3.5 9 ^{2}} = 1

What is (((x+1)^2)/4)+y^2=1 ?
The solution to (((x+1)^2)/4)+y^2=1 is Ellipse with (h,k)=(-1,0),a=2,b=1