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Beliebt Geometry >

2x^2+3y^2+12x=10

Lösung

2 x^{2} + 3 y^{2} + 12 x = 10

Lösung

(h, k) = (- 3, 0), a = 14, b = \frac{2 7}{3}

Schritte zur Lösung

2 x^{2} + 3 y^{2} + 12 x = 10

Rewrite

2 x^{2} + 3 y^{2} + 12 x = 10

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{( 14 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{2 7}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 0), a = 14, b = \frac{2 7}{3}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 3, 0), a = 14, b = \frac{2 7}{3}

Graph

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