What is ((x-5/2)^2)/9+(y^2)/(49)=1 ?

The solution to ((x-5/2)^2)/9+(y^2)/(49)=1 is Ellipse with (h,k)=(5/2 ,0),a=3,b=7

Popular >

((x-5/2)^2)/9+(y^2)/(49)=1

\frac{( x - \frac{5}{2} ) ^{2}}{9} + \frac{y ^{2}}{49} = 1

(h, k) = (\frac{5}{2}, 0), a = 3, b = 7

Solution steps

\frac{( x - \frac{5}{2} ) ^{2}}{9} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{( x - \frac{5}{2} ) ^{2}}{9} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - \frac{5}{2} ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (\frac{5}{2}, 0), a = 3, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (\frac{5}{2}, 0), b = 7, a = 3

\frac{( x + 4 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{16} = 1

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

2 = \frac{x ^{2}}{4} + \frac{y ^{2}}{9}

\frac{( x + 4 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{4} = 1

3 x^{2} + 2 y^{2} + 2 x - 3 y - 7 = 0

What is ((x-5/2)^2)/9+(y^2)/(49)=1 ?
The solution to ((x-5/2)^2)/9+(y^2)/(49)=1 is Ellipse with (h,k)=(5/2 ,0),a=3,b=7