What is the area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 ?

The area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 is A=6pi

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area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0

area

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

A = 6 π

Solution steps

A = π r^{2}

Find the radius

Radius given

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0 : r = 6

A = π (6)^{2}

Refine

A = 6 π

x^{2} + y^{2} = 36

x^{2} + y^{2} = 81

x^{2} + y^{2} = 9

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

What is the area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 ?
The area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 is A=6pi