en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 4x^2+4y^2-4x+2y-1=0

Solution

area

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

Solution

A = \frac{9 π}{16}

Solution steps

A = π r^{2}

Find the radius

Radius given

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0 : r = \frac{3}{4}

A = π (\frac{3}{4})^{2}

Refine

A = \frac{9 π}{16}

Popular Examples

area x^2+y^2=4 area

x^{2} + y^{2} = 4

area (x+4)^2+(y-6)^2=18 area

(x + 4)^{2} + (y - 6)^{2} = 18

area+x^2+y^2=4 area

+ x^{2} + y^{2} = 4

area 4x^2+4y^2=64 area

4 x^{2} + 4 y^{2} = 64

area x^2+y^2-6x+4y+4=0 area

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

Frequently Asked Questions (FAQ)

What is the area 4x^2+4y^2-4x+2y-1=0 ?
The area 4x^2+4y^2-4x+2y-1=0 is A=(9pi)/(16)