What is the circumference (x-2)^2+(y-3)^2=36 ?

The circumference (x-2)^2+(y-3)^2=36 is C=12pi

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circumference (x-2)^2+(y-3)^2=36

circumference

(x - 2)^{2} + (y - 3)^{2} = 36

C = 12 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 2)^{2} + (y - 3)^{2} = 36 : r = 6

C = 2 π 6

Refine

C = 12 π

x^{2} + y^{2} - 6 x + 2 y - 6 = 0

(x)^{2} + (y - 2)^{2} = 9

x^{2} + y^{2} - 6 x + 6 y - 3 = 0

x^{2} + y^{2} \geq 4

x^{2} + y^{2} \leq 16

What is the circumference (x-2)^2+(y-3)^2=36 ?
The circumference (x-2)^2+(y-3)^2=36 is C=12pi