What is the circumference x^2+y^2+2x-2y=0 ?

The circumference x^2+y^2+2x-2y=0 is C=2sqrt(2)pi

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circumference x^2+y^2+2x-2y=0

circumference

x^{2} + y^{2} + 2 x - 2 y = 0

C = 22 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 2 x - 2 y = 0 : r = 2

C = 22 π

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

x^{2} + (y - 3)^{2} = 25

(x + 1)^{2} + (y + 8)^{2} = 7

X^{2} + Y^{2} = 4

(x + 4)^{2} + (y - 3)^{2} = 16

What is the circumference x^2+y^2+2x-2y=0 ?
The circumference x^2+y^2+2x-2y=0 is C=2sqrt(2)pi